Calculate it’s fundamental frequency if the Young’s modulus of quartz crystal is$7.9 × 10^{10}N/m^2$and density is $2650 kg/m^3$.

Given Data :- $ t_1 = 1mm = 10^{(-3)}mm $

$Y = 7.9 × 10^{10}N/m^2$

$ ρ = 2650 kg/m^3$

Formula :- $f = 1/2t√Y/ρ$

Calculations :- $ f = 1/(2 × 10^{(-3)} ) √(7.9 ×10^{10})/2650 = 2.73 MHz$

Answers :- Frequency = 2.73 MHz