if:

1. $V_r$ = 0V
2. $V_r$ = 0.7V

Where $V_r$ is cut-in voltage

Given circuit is, parallel biased clamper.

Case-1:

Consider, Negative half-cycle of input, i.e. $V_i$ < 0

The equivalent circuit will be:

Now apply KVL to above circuit,

$V_c - V_i - 5 = 0$

$V_c = V_i + 5$

$V_c = 20 + 5$

$V_c = 25 V$

Also, $V_0 = 5V$

Case 2:

Consider positive half cycle, Diode will be reverse biased and acts as the open circuit shown below

Now, applying KVL to above circuit

$V_0 - V_i - V_c = 0$

$V_0 = V_i + V_c$

= 10 + 25

$V_0 = 35V$

Therefore output waveform for the given circuit :