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The transistor parameters in CB circuit in Fig Ex.4.13 are $h_{ie}=2.1k\Omega$ and $h_{fe}$=7.5 Calculate the circuit input and output impedances voltage gain
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written 5.5 years ago by
teamques10
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• modified 5.5 years ago |
$h_{ib}=\frac{h_{ie}}{1+h_{fe}}=\frac{2.1k\Omega}{1+75}$=27.6$\Omega$ ......(i)
$h_{fb}=\frac{h_{fe}}{1+h_{fe}}=\frac{75}{1+75}$=0.987 .........(ii)
Circuit input impedance. $Z_{i}=h_{ib}||R_{E}$
=$27.6\Omega|4.7k\Omega=27.4 \Omega$ ........(iii)
Circuit output impedance
$Z_{o}=(1/h_{cb})||R_{C}=R_{C}$
=3.9 k$\Omega$ .......(iv)
Voltage gain $A_{v}\frac{h_{fb}(R_{C}||R_{L})}{h_{fb}}$
=$\frac{0.987(3.9k\Omega||82k\Omega)}{27.6\Omega}$=133
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