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A gas occupying 0.26 $m^3$ at 300 degree C and 0.4 MPa pressure expands till volume becomes 0.441 $m^3$ and pressure 0.26 MPa.

written 7.4 years ago by teamques10 ★ 70k

•   modified 6.5 years ago

Calculate the change in internal energy per kg of gas Cp = 1 KJ/kgK, Cv = 0.71 KJ/kg k

thermodynamics

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written 7.4 years ago by teamques10 ★ 70k

•   modified 6.5 years ago

Cp - Cv = R

R =1-0.71=0.29

P2V2= MRT2

0.26×103 × 0.441 = 1×0.29 × T2

T2 = 114.66/ 0.29 = 395.370C

Change in internal energy per Kg of gas

ΔU = m × Cv (T2 – T1 )

= 1 × 0.71 ×(395.37-300) = 67.71 KJ/Kg

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