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Determine the maximum work obtainable from a Heat Engine exchanging heat with two finite bodies of equal heat capacities at temperature T1 and T2.
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A heat engine working between Higher temperature reservoir (T1) and lower Temperature reservoir (T2)

Let Q1 be the Heat absorbed by the heat Engine and Q2 be the Heat rejected by the Heat Engine.

Now Applying first Law of thermodynamics to above Heat engine

Σ W = Σ Q

Wnet = Q1 − Q2

For the Heat engine to be more efficient it has to be reversible as stated by Carnots theorem.

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