Shaft Power $P_{3}$=11772 kw

Head H=380m

N=750 rpm

overall efficiency, h0=0.86

i) Wheel diameter,D;

Velocity of jet $V_{1}=C\times\sqrt{2gH}$

=0.985$\sqrt{2\times 9.81\times 380}$

=85.05m\s

ku=$\frac{u}{V1}$=0.45

Wheel velocity u=$0.5\times 85.05$

=38.273 m/s

4=$\frac{\pi DN}{60}$

38.273=$\frac{\pi\times D\times 150}{60}$

D=0.975 m

ii) Diameter of jet d

Discharge jet q=$\frac{Q}{h}=\frac{4}{4}=1m^{3}/s$

q=$Area \ of \ jet\times V_{1}$ …