Subject Applied Hydraulics

Topics : Hydraulic Accumulator

Difficulty : Medium

A hydraulic press is a device which can be used to lift larger loads by the application of comparatively much smaller force

It consists of a ram which can move inside the larger cylinder. It has another small cylinder in which a plunger reciprocate.

When a small force, f is applied on the plunger, it presses the liquid below it. The pressure developed in the liquid will be 'p'. This pressure is transmitted we equally in all the directions according to pascal's law. This applied pressure raise of the ram. The heavier load W place on the the ram is thus lifted up.

let, A=Area of ram

a= Area of plunger

p= intensity of pressure

W= Weight lifted by ram

f= Applied Force called effort

Since intensity of pressure,p is same in all direction.The pressure at the bottom of plunger,

F=p.a or p=$\frac{F}{a}.........(i)$

Pressure at the bottom of ram

p=$\frac{w}{A}.............(ii)$

Equation 1 and 2 we get

$\frac{f}{a}=\frac{w}{A}$

w=F$\frac{A}{a}$

Mechanical advantage (M.A)=$\frac{load, W}{Effort,F}$

n=$\frac{w/A}{F/a}$

=$\frac{W}{F}.\frac{a}{A}$