0
4.7kviews
A hollow rectangular section 250 mm x 500 mm externally and has uniform thickness 50 mm, if the shear force at the section is 50kN. Find the maximum shear stress.
1 Answer
written 5.5 years ago by | • modified 5.5 years ago |
$I_{NA}=\frac{250*500^3}{12}-\frac{150*400^3}{12}$
$I_{NA}=1.8041*10^9 {mm}^4$
$q_{NA}=\frac{50*10^3(250*250*125-150*200*100)}{1.804*10^9*100}$
$q_{NA}=1.334 MPa$
$q_{11}=q_{22}=\frac{50*10^3(250*50*225)}{1.804*10^9*b}$
= 0.312MPa when b=200mm
= 0.779 MPa when b=100mm