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A compound bar is made up of steel rod 19mm in diameter surrounded by closely fitting brass tube of 32mm outside diameter and the two are securely fitted together at the ends.

Calculate the value of G for brass, if the angle of twist over a length of 1 meter is $7.2^\circ$, when the compound bar is subjected to a twisting couple 520 N-m. Also calculate the maximum shear stress in both the material if $G_s= 80 Mpa$.

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For composite bar

$\theta = \theta_B = \theta_S\\ T = T_B + T_S$

$\theta = 7.2^\circ = 0.1256\hspace{0.05cm}rad\\ \theta_B = \theta_S = 0.1256\\ T = 520\hspace{0.05cm}Nm = 520\hspace{0.05cm}\times\hspace{0.05cm}10^3\hspace{0.05cm}Nmm\\ J = \frac{\pi}{32}[D^4 - d^4]\\ \hspace{0.25cm} = \frac{\pi}{32}[32^4 - 19^4]\\ J = 90.14\hspace{0.05cm}\times\hspace{0.05cm}10^3\hspace{0.05cm}mm^4\\ R = \frac{D}{2} = 16\hspace{0.05cm}mm$

$\frac{T}{J} = \frac{G\theta}{L}\\ T …

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