It carries a load 80 kN at a point 5 cm away from the center of the section along one of the diagonals. Calculate the intensity of the stress at the corners of the column in the plan.

tan $\theta = \frac{300}{400}$

$sin \ \theta = \frac{300}{500} = 0.6$

$Area \ A = 400 \times 300 = 12 \times 10^4 \ mm^2$

$I_{xx} = \frac{400 \times 300^3}{12} = 900 \times 10^6 \ mm^4$

$I_{yy} = \frac{300 \times 400^3}{12} = 1.6 \times 10^9 \ mm^4 $

$p_d = \frac{P}{A}$ …