Locate core (i.e kernel) of the solid rectangular section of width 400 mm and depth 600 mm.

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written 7.1 years ago by

tarashankarsharma • 550

modified 6.1 years ago by

sanketshingote • 100

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written 6.1 years ago by

teamques10 ★ 70k

• modified 6.1 years ago

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[1] Area of section = $ 400 \times 600 = 24 \times 10^4 \ mm^2$

[2] Section modulus about XX – axis = $\frac{bd^2}{6} = \frac{400 \times 600^2}{6} = 24 \times 10^6 \ mm^3$

[3] Section modulus about YY – axis = $\frac{db^2}{6} = \frac{600 \times 400^2}{6} = 16 \times …

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written 7.1 years ago by

tarashankarsharma • 550

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