| written 7.1 years ago by | modified 3.8 years ago by |
Assume a reaction time of 2.5 sec, coefficient of friction as 0.6 and brake efficiency of 50% in either case.
Mumbai university > civil engineering > sem 5 > Transport Engineering 1
| written 7.1 years ago by | modified 3.8 years ago by |
Assume a reaction time of 2.5 sec, coefficient of friction as 0.6 and brake efficiency of 50% in either case.
Mumbai university > civil engineering > sem 5 > Transport Engineering 1
| written 7.1 years ago by |
Given
$V_1 = 65\hspace{0.05cm} kmph\hspace{1.5cm}V_2 = 55\hspace{0.05cm}kmph\\ \hspace{0.25cm} = 18.05\hspace{0.05cm}m/s\hspace{2cm} = 15.28\hspace{0.05cm}m/s\\ \\ t = \textit{reaction time} = 2.5\hspace{0.05cm}sec\\ f = \textit{coefficient of friction} = 0.6\\ \textit{Brake efficiency} = 50\% \hspace{0.05cm}of\hspace{0.05cm}0.6\\ f = \frac{50}{100}\times0.6 = 0.3$
Stopping Sight Distance
$SSD = (\textit{Log Distance + Breaking Distance})_1 + (\textit{Lag Distance + …