written 7.1 years ago by
teamques10
★ 70k
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modified 6.4 years ago
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(1)
$\textit{To find radius (l) of relative stiffness:}$
$P = \textit{Design wheel load} = 7500\hspace{0.05cm}kg$
$p = \textit{Contact pressure} = 7.5\hspace{0.05cm}kg/cm^2$
$\textit{We know},$
$a = \textit{Radius of load} = \sqrt{\frac{P}{p \pi}}$
$\hspace{03cm} = \sqrt{\frac{7000}{7.5\pi}} = 17.24\hspace{0.05cm}cm$
$\textit{TRIAL 1 : Assume pavement thickness (h) as 25 cm}$
$\hspace{02cm}\therefore h = 25\hspace{0.05cm}cm$ …
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