Calculate the stopping sight distance on a highway at a descending gradient of 2% for a design. Speed of 80kmph.Assume other data as per IRC standards if required

27kviews

written 7.1 years ago by

teamques10 ★ 70k

• modified 3.9 years ago

transportation engineering

ADD COMMENT EDIT

1 Answer

8.2kviews

written 7.1 years ago by

teamques10 ★ 70k

Descending gradient = 2%

V = 80 kmph = 22.22 m/sec

$SSD = Vt + \frac{V^2}{2g(f - \frac{\pi}{100})}....\textit{-ve for descending gradient}\\ = 22.22\times2.5 + \frac{22.22^2}{2\times9.81(0.35 - \frac{0.2}{100})}\\ = 127.86 m \approx128 m$

Create a free account to keep reading this post.

and 2 others joined a min ago.

ADD COMMENT EDIT

Please log in to add an answer.