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An oil of specific gravity 0.8 flows upwards through a vertical pipe. A &B are two points in the pipe, B being 30 cm higher than A

Connections are led from A & B to a U-tube containing mercury. If the difference of pressure between A &B is 0.18 $kg/cm^{2}$. Find the reading shown by the differential manometer.

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Given:

For the given configuration,

"specific gravity of the oil=$\frac{ρ _{oil}}{ρ _{water}} =0.8⟹{ρ}_{oil}=800 (since \ ρ_{water}≈1000 kg/m^{3})$

H=30 cm (potential difference between point A and B)

$∆P=P _A -P_B=0.18 kg/cm^2$(Static pressure difference between the two point A & B)

∴$∆P=0.18∙g 10^4 N/m^2$

To find: h (Reading shown by the mercury …

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