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The diameter of a pipe bend is 30 cm at inlet and 15 cm at outlet and the flow is turned through 120" ((angle measured in clockwise direction between direction of fluid flow at inlet and outlet)

in a vertical plane. The axis at inlet is horizontal and the centre of the outlet section is 1.5 m below the centre of the inlet section. Total volume of water in the bend is 0.9 m'. Neglecting friction, calculate the magnitude and direction of the force exerted on the bend by water flowing through it at 250 litress and when inlet pressure is 0.15 N/mm”.

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Given: angle of bend θ=$120^{\circ}$

Diameter of pipe at inlet $D_{1}$=30cm=0.30m

Diameter of pipe at outlet $D_{2}$=15cm=0.15m

Area at inlet , $A_{1}=\frac{π}{4} D1^{2}=0.0706m^2$

Area at outlet, $A_{2}=\frac{π}{4} D_2^{2}=0.01767m^2$

Pressure at inlet =$0.15N⁄mm^{2} =0.14×10^6 N⁄m^2 $

Q=250litres/sec=$0.25m^{3}sec$

$z_{2}$=-1.5m

$V_1=\frac{Q}{A_1} =\frac{.25}{.0706}$=3.541m/s

$V_2=\frac{Q}{A_2} =\frac{.25}{.01767}=14.1483m/s$

Applying Bernoulli’s equation at section 1 and 2

$\frac{p_1}{ρg}+\frac{V_1^{2}}{2g}+z_1=\frac{p_2}{ρg}+\frac{V_2^{2}}{2g}+z_2$ …

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