Mumbai University > Mechanical Engineering > Sem 4 > Production Process II

Marks: 5M

Also $r_{c}=\frac{t_{2}}{t_{1}}=\frac{cos(\phi-\alpha)}{sin \theta}$

uisng $\frac{V_{c}}{Sin[90-(\phi-\alpha)]}=\frac{V_{f}}{Sin\phi}$

Therefore, $V_{c}=\frac{V_{f}}{Sin\phi}\times Sin[90-(\phi-\alpha)]$

Therefore $V_{c}=V_{f}\times r_{c}$ $ \ \ \ $ but $ \ \ \ $ $sin [90-(\theta-\alpha)=cos(\phi-\alpha)]$

Hence proved