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Draw the Booth's algorithm and mutiply $(-3) \ast (4)$ using Booth's algorithm
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To perform $(4)*(-3)$

Here, $m^{n d}=8=0100$

$3+1=1100$

$3=0011$

$m^r = Q = (-3) = 1101$

$S_c = 4 (as \ count)$

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Here we get signed product in register.

AQ = 1111 0110

which is negative and it is in 2's compliment.

$\therefore 2's \ Complement = 0000 \ 1100$

$(4)*(-3) = (-12)_{10}$

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