Prove that for viscous flow through a circular pipe the kinetic energy correction factor is equal to 2 while momentum correction factor is equal to 4/3.

(10 Marks) May-2018

Subject Fluid Mechanics 2

Topic Laminar Flow

Difficulty Medium

A) Momentum correction factor or B.

The velocity distribution through a circular pipe for laminar flow at any radius 'r' is

$u = \frac{1}{4 \mu} (\frac{-\delta p}{\delta x}) (R^2 - r^2)$ ------- (1)

Now consider an elementary area dA in the form of a ring at a radius 'r' and …