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From the figure, λ = γ = 0 and VTh = 0.7 V
Source and drain exchange their roles.
VGS = 1 – $V_x$; V_DS = 1.9 - $V_x$; VDD = VGS - VTh = 0.3 - $V_x$
Device is in saturation region, so
Device turns off when $V_x$ = 0.3 V and never turns on again. So,
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