Derive the equation of contrast stretching transformation function as given in figure below.

3.2kviews

written 8.4 years ago by

teamques10 ★ 67k

• modified 4.4 years ago

Apply the contrast stretching transformation function on the input image F and obtain the output image R.

enter image description here

ADD COMMENT EDIT

1 Answer

65views

written 8.4 years ago by

teamques10 ★ 67k

• modified 8.4 years ago

Step 1: Derivation of Transform:

enter image description here

$S = \begin{bmatrix} αr & 0≤r≤a \ S_1+β(r-a) & a<r≤b \="" s_2+γ(r-b)="" &="" b<r≤l-1="" \="" \end{bmatrix}="" $<="" p="">

When a = 8, b = 12, L – 1 = 15

S1 = 4, S2 = 8

We get, α = 0.5, β = 1, γ …

Create a free account to keep reading this post.

and 5 others joined a min ago.

ADD COMMENT EDIT

Please log in to add an answer.