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Prove time convolution property of Fourier transform.
1 Answer
| written 9.5 years ago by |

Proof :
The convolution of the two signals in the time domain is defined as,




Using the definition of the Fourier transform of the RHS we get,
∴ F[$x_1 (t)* x_2 (t)]=X_1 (f)X_2 (f)$
This is the required result.