An electron enters a uniform magnetic field B=0.23$\times$10$^{-2}$ Wb/m$^{2}$ at 45$^{\circ}$ angle to B. Determine radius and the pitch of helical path.

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written 6.9 years ago by

vermavarsha432 • 1.0k

modified 5.6 years ago by

sanketshingote • 100

Assume electron speed to be 3$\times$10$^{7}$ m/s.

advanced engineering physics

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written 6.7 years ago by

teamques10 ★ 70k

Given:

$B = 0.23 \times 10^{-2} Wb/m^2$

$\theta = 45^0$

$v = 3 \times 10^7 m/s$

$R = ? $

$P = ? $

Solution:

$\begin{aligned} R &= \frac{mv \ sin\theta}{eB} \\ &= \frac{9.1 \times 10^{-31} \times 3 \times 10^7}{1.6 \times 10^{-17} \times 0.23 \times 10^{-2}} \times sin 45^0 \\ …

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