The requested tracks in the order received are 54, 57, 40, 20, 80, 120, 150, 45, 180. Apply the following disk scheduling algorithm starting track at 90.

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written 9.7 years ago by

teamques10 ★ 70k

• modified 9.7 years ago

a) FCFS

b) SSTF

c) C-SCAN

Marks: 10 M

Year: May 2015

operating systems

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1 Answer

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written 9.7 years ago by

teamques10 ★ 70k

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Total time travelled= $|90-54|+|54-57|+|57-40|+|40-20|+|20-80|+|80-120|+|120-150|+|150-45|+|45-180| =446$

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Total time take = $|90-80|+|80-57|+|57-54|+|54-45|+|45-40|+|40-20|+|20-120|+|120-150|+|150-180| =230$

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Total time take= $|90-120|+|120-150|+|150-180|+|180-200|+|200-0|+|0-20|+|20-40|+|40-45|+|45-54|+|54-57|+|57-80| =421$

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