written 14 months ago by
Ankit Pandey • 790

•
modified 13 months ago

Cellular system : FDD
Total bandwidth : $30 MHZ$
Channel bandwidth = $25 Khz * 2 Simplex \ Channels$
= $50 Khz/duplex \ channels$
Therefore,
Total available channels = $\frac{30,000}{50}$ = $600 Channels$
 For N=4
Total no. of channels = $\frac{600}{4}$ = $150 Channels$ available per cell.
 For N=7
Total no. of channels = $\frac{600}{7}$ = $85 Channels$ available per cell.
 For N=12
Total no. of channels = $\frac{600}{12}$ = $50 Channels$ available per cell.
 For N=13
Total no. of channels = $\frac{600}{13}$ = $46 Channels$ available per cell