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The waste water of a town is to be discharges into a river stream. The quantity of waste water produced per day is 7 million litres and its BOD is 260 mg/lit.
written 5.3 years ago by gravatar for akashgaikwad71 akashgaikwad71 • 280 modified 4.0 years ago by gravatar for prashantsaini prashantsaini • 0

If the discharge in the river is 160 lit/sec and its BOD is 5 mg/lit, find out the BOD of the diluted water.
industrial waste treatment
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written 5.1 years ago by gravatar for yashshah yashshah • 140 modified 5.1 years ago by gravatar for yashbeer yashbeer ★ 11k

Sewage discharge= $Q_s= \frac{7 \times 10^6}{24 \times 60 \times 60 } = 81.01 \ l/s$

Discharge of river = $Q_r= 160 \ l/s$

BOD of sewage = $C_s= 260 \ mg/l$

BOD of river = $C_r=5 \ mg/l$

BOD of diluted mixture = $C= \frac{C_s.Q_s + C_r.Q_r}{Q_s + Q_r }$ …

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