Given:-

Plate size 160 x 8mm

fy=250mpa=250N/mm$^{2}$

fu=410 mpa =410 N/mm$^{2}$

Required design strength tensile plate

1) Strength given by yielding gross section

Tdg=$\frac{Ag \times fy}{\gamma ma}=\frac{160 \times 8 \times 250}{11}$

Tdg=296.90 kN

2) Path ABC
An=$[(b-ndo)+\sum\frac{p^{2}}{4g}]\times t$

$[(160-3 \times18)+(0)] \times8$

An=848mm$^{2}$

Path ADEC

An=$[(160-4\times12)+(\frac{40^{2}}{4 \times 25} +\frac{40^{2}}{4\times 25})]xt$

An=960mm$^{2}$

strength govern by Rupture of net sectn

Tdn 0.9 x An x $\frac{fu}{\gamma ml}$

=0.9x848x$\frac{410}{1.25}$

=250.92KN

design strenght of plate 250.82kN