Given- Force=230KN fy=250mpa=250N/mm$^{2}$ fu=410N/mm$^{2}$ sw=4mm E.t.T=0.7$\times$4=2.8mm required- Design of tention member

Tdg==$\frac{Ag\times fy}{\gamma mo}$

AG=$\frac{Tdg\times \gamma mo}{fy}=\frac{230\times10^{3}\times1.1}{250}$

Ag=1012mm$^{2}$

provide 125$\times$75$\times$6mm

A provided=1166mm$^{2}$

P=(Leff$\times$ E.T.T)$\times \frac{fu}{\sqrt{3}\times \gamma mw}$ Assume work shop

230$\times10^{3}=(Leff)\times(0.7\times4)\times(\frac{410}{\sqrt{3}\times1.25}$

leff=4.33.76mm

provide leff=440mm

$\sum$mpx=0

(p$\times40.5)=(P1 \times$125)

P1=74.52KN

P1+P2=230

P2=155.48KN

P1=$lw_{1}\times0.7\times4\times\frac{410}{\sqrt{3}\times1.25}$

74.52-lw$_{1}$$\times0.7\times4\times\frac{410}{\sqrt{3}\times1.25}$ lw1=140.54mm 144.483=lw$\times$0.7$\times$4$\times\frac{410}{\sqrt{3}\times1.25}$

Lw$_2$=293.29mm

lw$_{2}$=299.46mm

1)Tdg=$\frac{Ag\times fy}{\gamma mo}=\frac{1166\times250}{1.1}$=265KN

2)Tdn=0.9$\times Anc \to,es\frac{fu}{\gamma ml}+BAgo\frac{fu}{\gamma mo}$

Anc=$(1255-\frac{6}{2})\times$6-

Anc=732mm$^{2}$

Agn=(75-$\frac{6}{2})\times6$

Ago=432mm$^{2}$

An=732+432

=1164mm$^{2}$

$B=1.4-0.076(\frac{w}{t})(\frac{fy}{fu})\times(\frac{bs}{lc})$

w=75mm

t=6mm

bs=75

Lc=440

B=1.7-0.076$(\frac{75}{6}(\frac{250}{410}(\frac{75}{440})$

B=1.30

Tdn=0.9$\times732\times\frac{250}{1.1}+1.30\times432\times\frac{410}{1.1}$

Tdn=343.72KN

Block shera

Tdb=$\frac{Avg.fy}{\sqrt{3}\gamma mo}+\frac{0.9 A+n fu}{\gamma ml}$

Tdb$_{2}$=$\frac{0.9\times Avn\times fm}{\sqrt{3}\times\gamma ml}+\frac{A+g.fu}{\gamma mo}$

Avm=Avg=299.46$\times6=179.76mm^{2}$

Afn=Afg=125$\times6=750mm^{2}$

Tdb$_{1}$=$\frac{1796.76\times250}{\sqrt{3}\times1.1}+\frac{0.9\times750\times410}{1.1}$

=457.16KN

Tdb$_{2}=\frac{0.9\times1796.76}{\sqrt{3}\times1.25}+\frac{750+250}{1.1}$

=459.06kN

design strenght of anlge 265 kN

least of(343.72kN,457.16kN)