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Design built-up section column carry axial factored load 1800 kN length of columns is 8m It is effectively held in position at both end & restrain again rotation at one end used steel fe410, fy250
written 6.8 years ago by gravatar for teamques10 teamques10 ★ 70k
design and drawing of steel structures
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written 6.8 years ago by gravatar for teamques10 teamques10 ★ 70k

Given

Pu = 1800kN = 1800$\times10^{3}$N

l=8m=8000mm

Left=KL

K=0.8......(IS. Pg 45. Clause)

Left =0.88$\times8000$

=6400mm

fe=410fy=250= mpa

Required = Built up section

Step I. Design of column section

Pd=Ae$\times$Fcd

1800$\times10^{3}=Ae\times150$

Ae=$\frac{1800\times10^{3}}{150}$

Area of each section = $\frac{1200}{2}=6000mm^{2}$

Provide two channel section

Ismc 400

Area= 6299mm${2}$

Ixx =15082.8$\times10^{4}$

Iyy=504.8$\times 10^{4} …

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