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A square group of 16 piles penetrate through the filled up soil of 3 m depth. The pile diameter is 250 mm and pile spacing is 0.75m.

The unit cohesion of material is 18kN/m$^{2}$ and unit weight of soil is 15kN/m$^{3}$. Compute negative skin friction given adhesion coefficient is 0.4.

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  • For individual piles: $$ \therefore \quad F_{n g}=16 \cdot F_{n}=16 \cdot \alpha \cdot \bar{c}_{u} \cdot\left(P_{s}\right) L_{c} $$ where $P_{s}=$ perimeter surface of the pile of dia $0.25 \mathrm{~m}$ $$ \begin{aligned} \pi d &=3.14 \times 0.25=0.785 \mathrm{~m} \\ L_{c} &=3 \mathrm{~m} \\ \bar{c}_{u} &=c_{u}=18 \mathrm{kN} / \mathrm{m}^{2} \\ \alpha &=0.4 \\ …

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