Pu=4105$\times10^{3}$N

For m20- CFL =20mpa

Step I.

Ap=$\frac{up}{0.6\ast fck}$

=$\frac{4105}{0.6\times 20}$

Ap=342.08$\times10^{3} mm^{2}$

Assume tg=16mm

$\neq$tf

$\gt $12.7mm

Safe

Assume ISA. 150$\times$ 115$\times$15 mm

2) width of plate(sp) =400+2(200)+2(16)+2(115)+2(24)

Bp=750mm

Lp$\frac{Ap}{Bp}=\frac{342.07\times 10^{3}}{750}$

Please=456.10

L=460mm

Step II

Thickness of base plate (tp)

Bmxx= at force of angle

By=$\frac{wl^{2}}{2}$. W=$\frac{our}{Ap}=\frac{4105\times 10^{3}}{750\times …