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Determine safe load p that can be carried by than as shown bolts are 20mm $\phi$ 4.6 grade.Thickness of bracket plate is 10mm
1 Answer
| written 6.8 years ago by |

Step I
list bolt value
shear capacity of bolt=$\frac{fub\times Anb\times nn}{\sqrt{3}Ymb}$
=$\frac{400\times 245\times 1}{\sqrt{3} \times 1.25}$
Vdsb=45.26 kN
bearing capacity of bolt=2$\times Kb\times d\times t\times $fu
find kb
$\frac{e}{3do}=\frac{40}{3\times 22}$=0.60
$\frac{P}{3do}$=0.25=$\frac{80}{3\times 22}$=0.25=0.96
$\frac{fub}{fu}=\frac{400}{410}$=0.97
Vdpb=$2\times0.6\times 20\times10\times 410$
Vdpb=98.4kN
Step II
Direct force per bolt or load in each bolt
F1=$\frac{load}{No.\ bolt …