Given

ISMB 250

bf=125m tf=12.5m tw=6.9

$\gamma$1=13m

ISHB 200 at 37.92 bf=200mm tf=9mm

tw=6.1mm

R=85kN(factored load)

$\phi$ of bolt=16mm

Anb=157mm$^{2}$

fub=4$\times$100=400N/mm$^{2}$

fy=250N/mm$^{2}$

fu=410N/mm$^{2}$

required no of bolts

shearing capacity of bolt =$\frac{fub\times Anb\times nn}{\sqrt{3}\times\gamma mb}$

=$\frac{400\times 157\times 1}{\sqrt{3}\times 1.25}$

Vdsb=29kN

bearing capacity of bolt=2$\times$K$\times$t$\times$d$\times$fu

Kb=$(\frac{e}{3d0},\frac{p}{3d0}-1, \frac{fyb}{fu},1)$ min value

Vdpb=2$\times0.56\times9\times16\times 410$ …