Steel beam flanges are embeded in concrete is 8m long c/c spacing =4m it carry Rcc slab 140m thick L.L =kN/m$^{2}$ F.F=1.5kN/m$^{2}$ Take fy=250 fe=410

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written 6.8 years ago by

teamques10 ★ 70k

modified 3.8 years ago by

pedsangini276 • 4.8k

design and drawing of steel structures

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written 6.8 years ago by

teamques10 ★ 70k

design internal beam b1 refer floor system enter image description here

Given

Span of beam=8m

Live load=4kN/m$^{2}$

Flour finish load=1.5kN/m$^{2}$

Fy=250

fe=410

Required=design internal beam B1

$\frac{Ly}{Lx}=\frac{8}{4}=2\geq$2 one way slab

$\frac{ly}{lx}\leq$2 two way slab

load on beam=slab load+wall load+Weight of beam

Concrete load=25$\frac{(kN}{ms})\times(4m)\times 0.140m$

=14kN/m

F.F.L=1.5$\times$4=6kNm

L.L =4$\times$4=16kN/m

slab load=concrete load+EFL+L.L

=14+6+16

=36kN/m

Assume …

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