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written 5.7 years ago by |

load for bending about Z axis =1.5[D.L +L.L]

=1.5[0.325+0.52]

=1.27kN/m

=1.2$\times$[D.2+L.L+W.L]

=1.2$\times$[0.325+0.52-1.31]

=-0.558kN/m

=0.9DL+1.5 WL\=(0.9$\ast 0.325+1.5\times$-1.31)

=-1.67kN/m

Load for bending about y axis =1.5[D.l+L.L]

=1.5[0.19+0..3]

=0.735kN/m

Calculation for Bending moment

Mz=1.27$\times \frac{42}{8}$=2.54 kN.m

Mz=-=1.67$\times\frac{42}{8}$=-3.34KN.m[section]

My=0.735$\times \frac{42}{8}$ =1.47 kNm

calculation of shear force

Fz=1.27$\times\frac{4}{2}$=2.54kN

Fy=0.735$\times\frac{4}{2}$=1.47

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