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written 5.7 years ago by |
load for bending about Z axis =1.5[D.L +L.L]
=1.5[0.325+0.52]
=1.27kN/m
=1.2$\times$[D.2+L.L+W.L]
=1.2$\times$[0.325+0.52-1.31]
=-0.558kN/m
=0.9DL+1.5 WL\=(0.9$\ast 0.325+1.5\times$-1.31)
=-1.67kN/m
Load for bending about y axis =1.5[D.l+L.L]
=1.5[0.19+0..3]
=0.735kN/m
Calculation for Bending moment
Mz=1.27$\times \frac{42}{8}$=2.54 kN.m
Mz=-=1.67$\times\frac{42}{8}$=-3.34KN.m[section]
My=0.735$\times \frac{42}{8}$ =1.47 kNm
calculation of shear force
Fz=1.27$\times\frac{4}{2}$=2.54kN
Fy=0.735$\times\frac{4}{2}$=1.47