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Solve the following.

If A = $\begin{bmatrix} \pi & \pi / 4 \\ 0 & \pi / 2 \\ \end{bmatrix}$ , Find $cosA$

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Given, A = $\begin{bmatrix} \pi & \pi / 4 \\ 0 & \pi / 2 \\ \end{bmatrix}$

Characteristic equation is given by

$\lvert A - \lambda I \lvert = 0$

$\begin{align} \begin{bmatrix} \pi- \lambda & \pi / 4 \\ 0 & \pi / 2 - \lambda\\ \end{bmatrix} = 0 \\ …

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Given, A = $\begin{bmatrix} \pi & \pi / 4 \\ 0 & \pi / 2 \\ \end{bmatrix}$

Characteristic equation is given by

$\lvert A - \lambda I \lvert = 0$

$\begin{align} \begin{bmatrix} \pi- \lambda & \pi / 4 \\ 0 & \pi / 2 - \lambda\\ \end{bmatrix} = 0 \\ …

Create a free account to keep reading this post.

and 2 others joined a min ago.

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