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Calculate karl pearson's coefficient of correlation between expenditure and sales from given data.
Adevertising Expenses (000 Rs) 39 65 62 90 82 75 25 98 36 78
Sales (Lakhs of Rupees) 47 53 58 86 62 68 60 91 51 84
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SR No. Advertising (X-90) Sales (Y-86) Product
X dx $dx^2$ y dy $dy^2$ dxdy
1 39 -51 2601 47 -39 1521 1989
2 65 -25 625 53 -33 1089 825
3 62 -28 784 58 -28 784 784
4 90 0 0 86 0 0 0
5 82 -8 64 62 -24 576 192
6 75 -15 225 68 -18 324 270
7 25 -65 4225 60 -26 676 1690
8 98 8 64 91 5 25 40
9 36 -54 2916 51 -35 1225 1890
10 78 -12 144 84 -2 4 24
N=10 $\sum{dx}= -250$ $\sum{dx^2}=11648$ $\sum{dy}=-200$ $\sum{dy^2}=6224$ $\sum{dxdy} = 7704$

$\begin{equation} r=\Bigg\{\frac{\sum{dxdy}-\frac{(\sum{dx})(\sum{dy})}{N}}{\sqrt{\sum{dx^2} -\frac{(\sum{dx^2})}{N}} \sqrt{\sum{dy^2} -\frac{(\sum{dy^2})}{N}}}\Bigg\} \\ r=\Bigg\{ \frac{7704- \frac{(-250)(-200)}{10}}{\sqrt{11648-\frac{(-250)^2}{10}} \sqrt{6224-\frac{(-200)^2}{10}}} \Bigg\} \\ r=\Bigg\{ \frac{7704- 5000}{\sqrt{11648-6250} \sqrt{6224-4000}} \Bigg\} \\ r=\Bigg\{ \frac{2704}{\sqrt{5398} \sqrt{2224}} \Bigg\} \\ r = 0.7804 \end{equation}$

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