Question: Find the velocity of a bullet fired in standard air

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**Given :** Mach angle $\alpha = 30˚$

R = 287 J/kg k

K = 1.4

Temperature t = 15˚ c

= 15 + 273 = 288˚ k

Now, Velocity of sound = $\sqrt {KRT}$

$= \sqrt {1.4 \times 287 \times 288}$

c = 340.17 m/s

Now, Mach angle,

Sin $\alpha = c/v$

i.e. Sin $30˚ = \frac{340.17}{V}$

$\therefore$ V = 680.34 m/s

$\therefore$ The velocity of a bullet fired in standard air is 680.34 m/s

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