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MODULE 6&7-Part 2 - Q.1

3-Hing Parabolic arch supported different level. Find:

1) Reaction

2)Max +ve & -ve B.M.

3)N & F at 3m from A.

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1 Answer
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Note: When $l_1$ & $l_2$ are not given first we have to calculate the $l_1$ & $l_2$ first.

Using formula

$l_1=\frac{l\sqrt{h_1}}{(\sqrt{h_1}+\sqrt{h_2})}$

$l_2=\frac{l\sqrt{h_2}}{(\sqrt{h_1}+\sqrt{h_2})}$

$l_1=\frac{l\sqrt{h_1}}{(\sqrt{h_1}+\sqrt{h_2})}=\frac{22.5\sqrt{3}}{(\sqrt{3}+\sqrt{6.75})}=9m$

$l=l_1+l_2$

$22.5=9+l_2$

$l_2=22.5-9=13.5m$

(1) Support $rx^n$ calculation:

Consider part (CA)

$BM_c=0$

$V_A\times 9-H\times 3-30\times 9\times \frac{9}{2}=0$

$9V_A-3H-1215=0$

$V_A=\frac{3H+1215}{9}$----------(1)

Consider part (CB)

$BM_c=0$

$V_B\times 13.5-H\times 6.75=0$

$V_B=\frac{6.75H}{13.5}$----------(2)

Put …

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