written 5.1 years ago by | modified 2.1 years ago by |
From the below figure, the gain of the amplifier is represented as A. the gain of the amplifier is the ratio of o/p. voltage ($v_o)$ to the input voltage (vi) the feedback network extracts a voltage vf = $\beta vo$ from the output vo of the amplifier.
- The output voltage is added for positive feedback from the signal voltage vs.
$\therefore$ vi = vs + vf
$\therefore$ vi = vs + $\beta vo$ → (1)
The quantity $\beta$ = vf/vo is the feedback ratio
Vo – A (vs + $\beta vo)$
$\therefore$ $\frac{vo}{vs}$ = $\frac{A}{1-A\beta}$
$\therefore$ AF = $\frac{vo}{vs}$ = $\frac{A}{1-A\beta}$
Where A$\beta$ = feedback factor or the loop gain of AB = 1, AF → $\infty$ thus the gain becomes infinity. i.e. there is o/p without any i/p hence we can see this amplifier works as one oscillator.
The condition A$\beta$ = 1 is called barkhausen’s criteria for oscillation.
a) The total phase shift through the amplifier and feedback network must be N x 360 where N = 0, 1, 2 ….
b) The magnitude of the loop gain must be unity.