written 5.1 years ago by
teamques10
★ 64k
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• modified 4.0 years ago |
| Activity | A (10-20) | B (10-30) | C (20-50) | D (30-40) | E (30-50) | F (40-50) |
|---|---|---|---|---|---|---|
| Duration | 8 | 11 | 6 | 5 | 8 | 5 |
| Labours | 3 | 4 | 2 | 5 | 3 | 3 |
i) Prepare histograms based on EST & LST Schedule.
ii) Which schedule you will prefer & why?
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written 5.0 years ago by
teamques10
★ 64k
|
i)
$\begin{aligned} \text { critical path } : B-D-F &=10-30-40-50 \\ \text { critical Activity } : B-D-F \end{aligned}$
$\text Project \ Duration: 11+5+5=21 \ days.$
ii) From histogram As per EST it is found that peak demand of carpenter goes on decreasing which results in smoothening of the carpenters requrement
| Activity | Duration | Carpenters | EST | EFT | LST | LFT |
|---|---|---|---|---|---|---|
| A | 8 | 3 | 0 | 8 | 7 | 15 |
| B | 11 | 4 | 0 | 11 | 0 | 11 |
| C | 6 | 2 | 8 | 14 | 15 | 21 |
| D | 5 | 5 | 11 | 16 | 11 | 16 |
| E | 8 | 3 | 11 | 19 | 13 | 21 |
| F | 5 | 3 | 16 | 21 | 16 | 21 |
As per LST
$\sum \ duration \times Resources^2$
= $(7 \times 4^2)+(4 \times 7^2)+(2 \times 8^2)+(2 \times 11^2)+(1 \times 10^2)+(5 \times 8^2)$
= $1098$
As per EST
= $(8 \times 7^2)+(3 \times 6^2)+(3 \times 10^2)+(2 \times 8^2)+(3 \times 6^2)+(2 \times 8^2)+$
= $1054$
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