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The pressure difference $\Delta$ P in a pipe of diameter D and and length l due turbulent flow depends velocity V Viscosity $\mu$,density $\rho$ and roughness K.
1 Answer
written 5.1 years ago by |
Using Buckingham's $\pi$ obtain expression $\Delta P$.
Solution:
$\Delta P$ is a function of $D,l,V,$ $\mu$,$\rho ,K$,
$\Delta P$=$f(D,l,V,\mu,\rho,k)$.....(1)
Total variables n=7
writing dimensions of each variable,
Dimension of $\Delta P$=Dimension of pressure
=$ML^{-1}T^{-2}$
D=L, l=L, $VLT^{-1}$
$\mu=ML^{-1}T^{-1}$
$\rho=ML^{-3}$
K=L
Number of fundamental dimensions M=3
No of $\pi$ terms …