If the energy dissipated in the model is$\frac{1}{10}kW$, What corresponding value in prototype?

Solution:

Given:

1) Liner scale ratio $L_r=20$

2) Height of hydraulic jump in mode = $h_m=0.20 m$

3) Energy dissipated in model , $P_m=\frac{1}{10}kW$

Step No (1)

$\frac{h_p}{h_m}=L_r$

=20

$h_p=h_m$ $\times$20

=0.20$\times$20

[$h_p=4m$]

Step No (2) Energy …

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