**Test cases using BVC**

Since there is only one variable for finding number is even or not, the total test cases will be 4n + 1 = 5

$\therefore$ min value = 0

maximum value = 200

minimum + value = 1

maximum - value = 199

nominal value = 100

Using this test cases designs are as follows.

Test case id | Integer value | Expected o/p |
---|---|---|

1 | 0 | even no. |

2 | 200 | even no. |

3 | 1 | odd no. |

4 | 199 | odd no. |

5 | 100 | even no. |

** Test cases using robust testing :**

$\therefore$ there is only one variable, total no. of test cases will be

6n + 1 = 7

min value = 0

max value = 100

min - value = -1

min + value = 1

max + value = 201

max - value = 199

nominal value = 100

Using these values, test cases can be designed as follows:

Test case ID | Integer value | Expected o/p |
---|---|---|

1 | 0 | even no. |

2 | 200 | even no. |

3 | -1 | odd no. |

4 | 1 | odd no. |

5 | 201 | odd no. |

6 | 199 | odd no. |

7 | 100 | even no. |

**Test cases using worst case testing :** Since there is only one variable, the total number of test cases will be $5^n = 5$ Therefore the number of test cases will be same as BVC.