Calculate the output statistics for the queueing system whose inter-arrival and service times for ten arrivals are given below.

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written 5.1 years ago by

teamques10 ★ 65k

• modified 4.0 years ago

Inter-arrival time	-	1	1	6	3	7	5	2	4	1
Service time	4	2	5	4	1	5	4	1	4	3

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written 5.1 years ago by

teamques10 ★ 65k

• modified 4.7 years ago

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o/p statistics

$Avg \ waiting \ time = \frac{total \ waiting \ time}{no. \ of \ cost}$

$= \frac{19}{10} = 1.9$ mins

Problem That cost has to wait = $\frac{no. \ of \ cost \ who \ wait}{no. \ of \ cost}$

$= \frac{6}{10} = 0.6$

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