| written 9.5 years ago by | • modified 9.5 years ago |
Mumbai University > Information Technology > Sem3 > Analog and Digital Circuits
Marks: 10M
Year: May 14
| written 9.5 years ago by | • modified 9.5 years ago |
Mumbai University > Information Technology > Sem3 > Analog and Digital Circuits
Marks: 10M
Year: May 14
| written 9.5 years ago by |
The function of an ideal differential amplifier is to amplify the difference between two input signals.
Following is the circuit diagram for a differential amplifier.

Many electronic devices use differential amplifiers internally.
The output of an ideal differential amplifier is given by:
$V_{out}=A_d(V_{in}^+-V_{in}^ -)$
Where $(V_{in}^+) $ and $(V_{in}^-)$ are the input voltages and $A_d$ is the differential gain.
In practice, however, the gain is not quite equal for the two inputs.
This means, for instance, that if $(V_{in}^+) $ and $(V_{in}^-)$ are equal, the output will not be zero, as it would be in the ideal case.
A more realistic expression for the output of a differential amplifier thus includes a second term.
$V_{out}=A_d(V_{in}^+-V_{in}^ -) +A_c(\frac{V_{in}^+-V_{in}^ -}{2})$
is called the common-mode gain of the amplifier.
$A_c$ As differential amplifiers are often used to null out noise or bias-voltages that appear at both inputs, a low common-mode gain is usually desired.