1000 kg/$cm^2$. The modulus of elasticity of the metal is 2 × ${10}^6$ kg/c$m^3$. Calculate the percentage change in the resistance of the strain gauge. What is the value of Poisson’s ratio?

Gauge Factor $G_f$=2

Stress =1000 kg/$(cm)^2 $

Modulus of elasticity=ε=2×$(10)^6$ kg/$(cm)^3$

Formulae –

Modulus of elasticity=ε=$\frac{Stress}{Strain}$

Change in Resistance=$∆R=G_f$×Strain

Poisson's ratio=$μ=(G_f-1)/2$

Solution –

Before we calculate the change in resistance, we have to deduce the value of strain. Strain is given by the ratio of stress and modulus of elasticity, …