$V_{DS}=5V, V_{GS}=5V, V_{BS}=0V, W=10µm, L=5 µm, k'n=100mA/V^2$ and $V_{TO}=1V$.Calculate its drain current for channel length modulation factor of $λ$ of 0 and $0.25V^{-1}$. -

Mumbai University > EXTC > Sem 3 > Analog Electronics 1

Marks: 4 M

Year: May 2014

• $I_{DS}=\frac{W}{L} (\frac{µCox}{2})(V_{GS}-V_{TO})^2(1+λV_{DS})$

  Put $k_n΄=\frac{µCox}{2}$

  Therefore equation becomes

• $I_{DS}=\frac{W}{L} k_n΄*(V_{GS}-V_{TO})2(1+λV_{DS})$

  1.$For λ=0$

  $I_{DS}=\frac{10}{5}* 100×10^{-3}*1$

  $=200mA$

  $\boxed {I_{DS}=0.2A}$

  2. For $λ=0.25$

  $I_{DS}=\frac{10}{5}* 100×10-3(1+(0.25×5))$

  $=200×10-3×2.25$

  $\boxed{I_{DS} =0.45A}$