The emitter bias configuration as shown in following figure has the specifications.

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written 6.5 years ago by

teamques10 ★ 70k

modified 3.6 years ago by

pedsangini276 • 4.8k

electronic circuits and communication

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1 Answer

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written 3.6 years ago by

sagarkolekar ★ 11k

• modified 3.6 years ago

$I_{cq} = \frac{1}{2}$ $I_{csat}$

$I_{csat} = 8 \ mA$

$V_c = 18 \ v$ and $B = 110$

Determine $R_c, R_t$ and $R_B$

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Solution:

$\because$ $1_c = \frac{1}{2} 1 \ csat$

$1_c = \frac{1}{2} (8 \ MA) = 4 \ MA $

: $\because$ $\frac{28-vc}{Rc} = 1_c$

$\frac{28-18}{Rc} = HMA$ …

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