Choose the filter implementation that requires least number of components

The First step to compute the normalize frequency Ω at which attenuation should be 50dB we observed that the

$\Omega = \frac{250MHz}{200MHz} = 1.25.................\Omega = w / w_c$

Since the flatness of filter response is not a design consideration. Hence the filter of implementation with requires least number of components is Equi-Ripple Filter

From 3.0dB Ripple graph we come to know that for $(ω/ω_c -1)$ and attenuation 50dB we have curvature intersection at N=9

Hence order of filter N= 9

Hence components of Chebyschev filter are

C1 = 3.5384       C5= 4.7272

L2 = 0.7771       L6 =0.8118

C3 = 4.6692       C7=4.6692

L4 = 0.8118       L8 =0.7760

C9 =3.5340

Graphical Representation of Implemented Filter function Response: